a: 3km75m=3,075m
\(\dfrac{1}{4}m^2=25dm^2\)
3h15'=195p
b: 26320:35=752
c: =3/5(5/12+7/12)
=3/5
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a, \(3km75m=3075m\)
\(\dfrac{1}{4}m^2=25\text{d}m^2\)
`3` giờ `15` phút = `195` phút
b,
`->26320 : 35=752.`
c, \(\dfrac{9}{15}\times\dfrac{5}{12}+\dfrac{9}{15}\times\dfrac{7}{12}=\dfrac{9}{15}\times\left(\dfrac{5}{12}+\dfrac{7}{12}\right)=\dfrac{9}{15}\times1=\dfrac{9}{15}\)
`@mt`
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