Question

(8x-16).(x-4³)=0

Ai trả lời đúng thì tui tick cho:))))))))))

Answer 1

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\(\left(8x-16\right)\cdot\left(x-4^3\right)=0\)

\(\Rightarrow\) \(\left[{}\begin{matrix}8x-16=0\\x-4^3=0\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}8x=16\\x=64+0\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=16\div8\\x=64\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=2\\x=64\end{matrix}\right.\)

Vậy, \(x\in\left\{2;64\right\}\)

Answer 2

(8\(x\) -16)(\(x-4^3\)) = 0

\(\left[{}\begin{matrix}8x-16=0\\x-4^3=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}8x=16\\x=64\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=2\\x=64\end{matrix}\right.\)

Vậy \(x\in\) { 2; 64}

 

Answer 3

Kurouba ryousuke

4³ mà em ơi

4³ = 64 mà em

Answer 4

Nguyễn Thị Thương Hoài

Dạ e sửa rồi ạ