\(=\dfrac{-7}{8}\cdot\dfrac{16}{21}-\dfrac{5}{3}\cdot\dfrac{2-7}{10}=\dfrac{-2}{3}+\dfrac{5}{6}=\dfrac{1}{6}\)
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\(=\dfrac{-7}{8}\cdot\dfrac{16}{21}-\dfrac{5}{3}\cdot\dfrac{2-7}{10}=\dfrac{-2}{3}+\dfrac{5}{6}=\dfrac{1}{6}\)