H24

6x/x mũ 2-9+5x/x-3+x/x+3

DM
3 tháng 1 2022 lúc 13:54
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NT
3 tháng 1 2022 lúc 13:55

\(=\dfrac{6x}{\left(x-3\right)\left(x+3\right)}-\dfrac{9+5x}{x-3}+\dfrac{x}{x+3}\)

\(=\dfrac{6x-\left(5x+9\right)\left(x+3\right)+x^2-3x}{\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{x^2+3x-5x^2-15x-9x-27}{\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{-4x^2-21x-27}{\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{-\left(4x^2+12x+9x+27\right)}{\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{-4x-9}{x-3}\)

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