`(6x-7)^4=625=(5)^4=(-5)^4`
`=>[(6x-7=5),(6x-7=-5):}`
`=>[(6x=12),(6x=2):}`
`=>[(x=2),(x=1/3):}`
Vậy `x=2` hoặc `x=1/3.`
(6x - 7)4 = 625
⇔ 6x - 4 = 5
⇔ 6x = 9
⇔ x = \(\dfrac{9}{6}=\dfrac{3}{2}\)
Ta có: \(\left(6x-7\right)^4=625\)
\(\Leftrightarrow\left[{}\begin{matrix}6x-7=5\\6x-7=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}6x=12\\6x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{3}\end{matrix}\right.\)