Question

6x-2phần x+4 bằng 5

Answer 1

\(\dfrac{6x-2}{x+4}=5\Leftrightarrow6x-2=5x+20\)

\(\Leftrightarrow x=22\)

Answer 2

\(\dfrac{6x-2}{x+4}=5\)

ĐKXĐ:  \(x\ne-4\)

\(\dfrac{6x-2}{x+4}=\dfrac{5\left(x+4\right)}{x+4}\)

\(6x-2=5x+20\)

\(6x-5x=20+2\)

\(x=22\)

Vậy \(S=\left\{22\right\}\)

 

Answer 3

\(\dfrac{6x-2}{x+4}=5\left(dkxd:x\ne-4\right)\)

Suy ra :

\(6x-2=5\left(x+4\right)\)

\(\Rightarrow6x-2=5x+20\)

\(\Rightarrow x=22\left(tmdk\right)\)

Vậy \(S=\left\{22\right\}\)

Answer 4

\(\dfrac{6x-2}{x+4}=5\text{ĐKXĐ:}x\ne-4\)

\(\Leftrightarrow\dfrac{6x-2}{x+4}=\dfrac{5\left(x+4\right)}{x+4}MTC:x+4\)

\(\Rightarrow6x-2=5x+20\)

\(\Leftrightarrow6x-2-5x-20=0\)

\(\Leftrightarrow x-22=0\)

\(\Leftrightarrow x=22\)

\(\text{Vậy phương trình có tập nghiệm là }S=\left\{22\right\}\)