Question

6) \(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)

Answer 1

\(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)

\(=\left(-16-\dfrac{2}{7}\right)\cdot\dfrac{5}{3}+\left(28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)

\(=12\cdot\dfrac{5}{3}=20\)