ĐKXĐ \(x\ge\dfrac{1}{2}\)
\(\Leftrightarrow\left(4x^2-4x\sqrt{x+3}+x+3\right)+\left(2x-1-2\sqrt{x-1}+1\right)=0\)
\(\Leftrightarrow\left(2x-\sqrt{x+3}\right)^2+\left(\sqrt{2x-1}-1\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-\sqrt{x+3}=0\\\sqrt{2x-1}-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x=\sqrt{x+3}\\2x-1=1\end{matrix}\right.\) \(\Rightarrow x=1\)
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