Question

(4x-5)/3>(7-x)/5

Answer 1

\(\dfrac{4x-5}{3}>\dfrac{7-x}{5}\\ \Leftrightarrow\dfrac{\left(4x-5\right)5}{15}>\dfrac{\left(7-x\right)3}{15}\\ \Leftrightarrow20x-25>21-3x\\ \Leftrightarrow20x+3x>21+25\\ \Leftrightarrow23x>46\\ \Leftrightarrow x>2\)

Answer 2

=>5(4x-5)>3(7-x)

=>20x-25>21-3x

=>23x>46

=>x>2

Answer 3

`(4x-5)/(3)>(7-x)/(5)`

`<=>(5.(4x-5))/(3.5) > (3.(7-x))/(5.3)`

`<=>(20x-25)/(15) > (21-3x)/(5.3)`

`<=>20x-25>21-3x`

`<=>20x+3x > 25+2`

`<=>23x>46`

`<=>x>2`

Vậy `x>2`