\(\Leftrightarrow\dfrac{4}{x-1}-\dfrac{5}{x-2}=-3\)\(\Leftrightarrow4x-8-5x+5+3\left(x-1\right)\left(x-2\right)=0\)\(\Leftrightarrow3\left(x^2-3x+2\right)-x-3=0\)\(\Leftrightarrow3x^2-9x+6-x-3=0\)\(\Leftrightarrow3x^2-10x+3=0\)=>(3x-1)(x-3)=0=>x=1/3 hoặc x=3Câu trả lời: \(\Leftrightarrow\dfrac{4}{x-1}-\dfrac{5}{x-2}=-3\)\(\Leftrightarrow4x-8-5x+5+3\left(x-1\right)\left(x-2\right)=0\)\(\Leftrightarrow3\left(x^2-3x+2\right)-x-3=0\)\(\Leftrightarrow3x^2-9x+6-x-3=0\)\(\Leftrightarrow3x^2-10x+3=0\)=>(3x-1)(x-3)=0=>x=1/3 hoặc x=3