Question

(4n-3)chia hết(n+2)

Answer 1

Ta có: \(4n-3⋮n+2\)

=>\(4n+8-11⋮n+2\)

=>\(-11⋮n+2\)

=>\(n+2\in\left\{1;-1;11;-11\right\}\)

=>\(n\in\left\{-1;-3;9;-13\right\}\)