Question

(3x+1)^2-9x(x+2)=x-1

Answer 1

`(3x+1)^2-9x(x+2)=x-1`

`<=>9x^2+6x+1-9x^2-18x=x-1`

`<=>-12x+1=x-1`

`<=>-13x=-2`

`<=>x=2/13`

Answer 2

\(\left(3x+1\right)^2-9x\left(x+2\right)=x-1\)

\(\Leftrightarrow9x^2+6x+1-9x^2-18x=x-1\)

\(\Leftrightarrow-12x+1=x-1\Leftrightarrow-13x+2=0\Leftrightarrow x=\dfrac{2}{13}\)

Answer 3

chubabi

Answer 4

Ta có: \(\left(3x+1\right)^2-9x\left(x+2\right)=x-1\)

\(\Leftrightarrow9x^2+6x+1-9x^2-18x-x+1=0\)

\(\Leftrightarrow-13x=-2\)

hay \(x=\dfrac{2}{13}\)