Question

\(3^x\) + \(\sqrt{4}\)  x 3\(^{x+1}\) = \(3^2\) x \(\sqrt{49}\)

 

Answer 1

\(3^x+\sqrt{4}.3^{x+1}=3^2.\sqrt{49}\)
\(3^x+2.3^x.3=9.7\)
\(3^x+3^x.6=63\)
\(3^x.\left(1+6\right)=63\)
\(3^x.7=63\)
\(3^x=63:7\)
\(3^x=9\)
\(3^x=3^2\)
\(x=2\)
Vậy ....