(3x-1)(x+3)=(2-x)(5-3x)
=> 3x2 + 8x - 3= 3x2 -11x +10
=> 19x=13
=> x=13/19
Vậy S=(13/19).
Chúc bạn học tốt
\(\text{(3x-1)(x+3)=(2-x)(5-3x) }\)
\(\Leftrightarrow3x^2-x+9x-3=10-6x-5x+3x^2\)
\(\Leftrightarrow8x-3=-11x+10\)
\(\Leftrightarrow19x=13\)
\(\Leftrightarrow x=\frac{13}{19}\)
Đề là gì hả bạn giải phương trình à
Ta có (3x-1)(x+3)=(2-x)(5-3x)
<=>3x2+8x-3=10-11x+3x2
<=>8x-3=10-11x
<=>8x+11x=10+3
<=>19x=13
<=>x=\(\frac{13}{19}\)
Làm j 1 bài mà 3 bạn giải
1) x2 - x - (3x - 3) = 02) x(x - 6) - 7x + 42 = 0
3) x3 - 3x2 + 3x - 1 = 0
4) (2x - 5)2 - (x + 2) 2 = 0
5) x(2x - 9) = 3x(x - 5)
giải phương trình 1)\(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2\right)+1}{x^2-4}\)2) \(\dfrac{3x+2}{3x-2}-\dfrac{6}{2+3x}=\dfrac{9x^2}{9x^2-4}\)3) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)4) \(\dfrac{x-1}{x}+\dfrac{1}{x+1}=\dfrac{2x-1}{2x^2+2}\)5) \(\dfrac{2}{x+1}+\dfrac{3x+1}{x+1}=\dfrac{1}{\left(x+1\right)\left(x-2\right)}\)
bài 2
a 0,75x (x +5 )= x+5 (3- 1,25x)
b\(\frac{4}{5}x-3=\frac{1}{5}x\left(4x-15\right)\)
c(x-3) -\(\frac{\left(x-3\right)\left(2x-5\right)}{6}=\frac{\left(x-3\right)\left(3-x\right)}{4}\)
d \(\frac{\left(3x+1\right)\left(3x-2\right)}{3}+5\left(3x+1\right)=\frac{2\left(2x+1\right)\left(3x+1\right)}{3}+2x\left(3x+1\right)\)
giải phương trình
[x - 6] [ 2x -5 ] [ 3x + 9 ] = 0
2x [ x - 3 ] + 5 [ x - 3 ] = 0
[ 4 - x ]2 - [ x - 2 ] [ 3 - 2x ] = 0
3x [x2 + 1 ] [ x - 2 ] =0
[ 3x + 5 ] [ x2 + x + 1 ] = 0
Giải các phương trình
1,\(3x-1=0\\\) 4, \(\dfrac{x}{3}-\dfrac{x}{5}=4\)
2, \(2-x=3x+1\) 5, \(\dfrac{x-1}{4}+\dfrac{2x+1}{6}=\dfrac{3}{2}\)
3, \(2\left(x-2\right)-1=5x\)
Giải phương trình
1) 16-8x=0
2) 7x+14=0
3) 5-2x=0
4) 3x-5=7
5) 8-3x=6
6) 8=11x+6
7)-9+2x=0
8) 7x+2=0
9) 5x-6=6+2x
10) 10+2x=3x-7
11) 5x-3=16-8x
12)-7-5x=8+9x
13) 18-5x=7+3x
14) 9-7x=-4x+3
15) 11-11x=21-5x
16) 2(-7+3x)=5-(x+2)
17) 5(8+3x)+2(3x-8)=0
18) 3(2x-1)-3x+1=0
19)-4(x-3)=6x+(x-3)
20)-5-(x+3)=2-5x
gải phương trình
a 3(x-2)+15=5(2-3x)
b 4x(x-1)-(x+3)(x-3)=9
c (3x-1)(4x+3)+2(3x-1)=0
d (2x-1)2=(8x+3)(2x-1)
1) (3x - 2)(4x + 5) = 0
2) (4x + 2)(x2 + 3) = 0
3) (2x + 7)(x - 3)(5x - 1) = 0
4) x2 - 3x = 0
5) x2 - x = 0
1) (x+5)(x+2)-3(4x-3)=(5-x)2
2) (x+2)3-(x-2)3=12x(x-1)-8
3) 3x(12x-4)-9x(4x-3)=30
4) (12x-5)(4x-1)+(3x-7)(1-16x)=81