Question

\((3x-1)(x^2+2)=(3x-1)(7x-10)\)

Answer 1

`(3x-1)(x^2+2)=(3x-1)(7x-10)`

`<=> (3x-1)(x^2+2)-(3x-1)(7x-10)=0`

`<=>(3x-1)(x^2+2-7x+10)=0`

`<=>(3x-1)(x^2-7x+12)=0`

 \(\Leftrightarrow\left[{}\begin{matrix}3x-1=0\\x^2-7x+12=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=3\\x=4\end{matrix}\right.\)

Vậy `S={1/3 ; 3;4}`.

Answer 2

pt <=> (3x-1)(x\(^2\)+2-7x+10)=0

<=> (3x-1)(x\(^2\)-7x+12)=0

<=> \(\left[{}\begin{matrix}3x-1=0\\x\text{​​}^2-7x+12=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=\dfrac{1}{3}\\\left(x-4\right)\left(x-3\right)=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x+\dfrac{1}{3}\\x=4\\x=3\end{matrix}\right.\)

Answer 3

=(3x-1)(x^2+2)-(3x-1)(7x-10)=0 =(3x-1)(x^2+2-7x+10)=0 =(3x-1)(x^2-7x+12)=0 =(3x-1)(x^2-4x-3x+12)=0 =(3x-1){(x^2-4x)-(3x-12)}=0 =(3x-1){x(x-4)-3(x-4)}=0 =(3x-1)(x-3)(x-4)=0 =3x-1=0 hoặc x-3=0 hoặc x-4=0 3x-1=03x=1x=1\3 x-3=0x=3 x-4=0x=4