Question

3^2x-1=27

Answer 1

=>2x-1=3

=>2x=4

=>x=2

Answer 2

\(3^{2x-1}=27\)

\(\Rightarrow3^{2x-1}=3^3\)

\(\Rightarrow2x-1=3\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)
Vậy \(x=2\)

Answer 3

\(3^{2x-1}=27\\\Rightarrow3^{2x-1}=3^3\\ \Rightarrow2x-1=3\\ \Rightarrow2x=4\\ \Rightarrow x=2\)