Question

(3 và 4/5 - 2x)*(1/3+x)=0    

         nhanhh ạ

Answer 1

=>3,8-2x=0 hoặc x+1/3=0

=>x=1,9 hoặc x=-1/3

Answer 2

\(\left(3\dfrac{4}{5}-2x\right)\cdot\left(\dfrac{1}{3}+x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}3\dfrac{4}{5}-2x=0\\\dfrac{1}{3}+x=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{19}{5}\\x=-\dfrac{1}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{19}{10}\\x=-\dfrac{1}{3}\end{matrix}\right.\)

Answer 3

\(\left(3\dfrac{4}{5}-2x\right).\left(\dfrac{1}{3}+x\right)=0\)

\(\Leftrightarrow\left(\dfrac{19}{5}-2x\right).\left(\dfrac{1}{3}+x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{19}{5}-2x=0\\\dfrac{1}{3}+x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}-2x=-\dfrac{19}{5}\\x=-\dfrac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{19}{10}\\x=-\dfrac{1}{3}\end{matrix}\right.\)