\(3^2\cdot\dfrac{1}{243}\cdot81^2\cdot\dfrac{1}{9}\)
\(=\dfrac{3^2}{3^5}\cdot\dfrac{\left(3^4\right)^2}{3^2}=\dfrac{3^8}{3^5}\cdot\dfrac{3^2}{3^2}=3^3\)
=27
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