Question

( 3 - \(\dfrac{3}{4}\) ) x ( 3 - \(\dfrac{3}{3}\) ) x ( 3 - \(\dfrac{3}{2}\) ) x ( 3 - \(\dfrac{3}{1}\) ) + 2019

Answer 1

\(\left(3-\dfrac{3}{4}\right)\times\left(3-\dfrac{3}{3}\right)\times\left(3-\dfrac{3}{2}\right)\times\left(3-\dfrac{3}{1}\right)+2019\)

=\(\left(3-\dfrac{3}{4}\right)\times\left(3-\dfrac{3}{3}\right)\times\left(3-\dfrac{3}{2}\right)\times0+2019\)

=\(0+2019\)

=2019

Answer 2

Ta có: \(\left(3-\dfrac{3}{4}\right)\left(3-\dfrac{3}{3}\right)\left(3-\dfrac{3}{2}\right)\left(3-\dfrac{3}{1}\right)+2019\)

\(=\dfrac{6}{4}\cdot2\cdot\dfrac{3}{2}\cdot0+2019\)

=2019