=>3(3x-1/2)^3=-1/9
=>(3x-1/2)^3=-1/27
=>3x-1/2=-1/3
=>3x=1/6
=>x=1/18
=>3(3x-1/2)^3=-1/9
=>(3x-1/2)^3=-1/27
=>3x-1/2=-1/3
=>3x=1/6
=>x=1/18
(x2 + 9) (9x2 -1) = 0
(4x2 -9) (2x-1 -1) =0
( 3x+2) (9-x2 ) =0
(3x+3)2 ( 4x - 42 ) =0
2(x-5) ( x+2) =1
3.(3x-1/2)^3+1/9=0
3 ( 3x -1/2 )^3 + 1/9 = 0
a) (2x+3/5)2-9/25=0
b)3(3x-1/2)3+1/9=0
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
- Tìm x
2 . ( x - 1/2 ) ^ 3 - 1/4 = 0
( 3x -1 ) ( - 1/2x + 5 ) = 0
( 2n + 3/5 ) ^ 2 - 9/25 = 0
3 ( 3n - 1/2 ) ^ 3 + 1/9 = 0
tìm X
1/4+2.(3.x-2/3)=1
(1/2+2X). (2x-3)=0
(4x-5).(5/4.x-2)=0
1/9-(2.x+1/2)mũ 2=0
9.(3x-1/2)mũ 2 =4
1/2.x+2/3.x-1=-10/3
X+1/12=-3/9
Tìm x biết:
a) (2x + 3/5)^2 - 9/25 = 0
b) 3.(3x - 1/2)^3 +1/9 =0
(2x+3/5)^2-9/25=0
3(3x-1)^3+1/9=0
nêu cách làm