Question

3) (2x + 1) : 9 - 104:13 = 27 ^ 2 :  3 ^ 5

Answer 1

`@` `\text {Ans}`

`\downarrow`

`3)`

`(2x + 1) \div 9 - 104 \div 13 = 27^2 \div 3^5`

`\Rightarrow (2x + 1) \div 9 - 8 = (3^3)^2 \div 3^5`

`\Rightarrow (2x + 1) \div 9 - 8 = 3^6 \div 3^5`

`\Rightarrow (2x + 1) \div 9 - 8 = 3`

`\Rightarrow (2x + 1) \div 9 = 3 + 8`

`\Rightarrow (2x + 1) \div 9 = 11`

`\Rightarrow 2x + 1 = 11 . 9`

`\Rightarrow 2x + 1 = 99`

`\Rightarrow 2x = 99 - 1`

`\Rightarrow 2x = 98`

`\Rightarrow x = 98 \div 2`

`\Rightarrow x = 49`

Vậy, `x = 49.`

Answer 2

3) \(\left(2x+1\right):9-104:13=27^2:3^5\)

     \(\left(2x+1\right):9-8=729:243\)

     \(\left(2x+1\right):9-8=3\)

     \(\left(2x+1\right):9=8+3\)

      \(\left(2x+1\right):9=11\)

       ( 2x + 1)  = 11.9

        2x+1 = 99

        2x  = 99-1

        2x   = 98

        x = 98 : 2

        x = 49