(2\(x\) + 11) ⋮ (\(x+5\)) (đk \(x\) ≠ - 5)
2\(x\) + 10 + 1 ⋮ \(x+5\)
2.(\(x+5\)) + 1 ⋮ \(x+5\)
1 ⋮ \(x+5\)
\(x+5\) \(\in\) Ư(1) = {-1; 1}
\(x\) \(\in\) {-6; - 4}
Vậy \(x\) \(\in\) {-6; -4}
\(\left(2x+11\right)⋮\left(x+5\right)\)
\(\Rightarrow\left(2x+10+1\right)⋮\left(x+5\right)\)
\(\Rightarrow\left[2\left(x+5\right)+1\right]⋮\left(x+5\right)\)
\(\Rightarrow1⋮\left(x+5\right)\)
\(\Rightarrow x+5\inƯ\left(1\right)=\left\{-1;1\right\}\)
\(\Rightarrow x\in\left\{-6;-4\right\}\)