Question

(-2)^x / 16 = -2^3

Answer 1

=>(-2)^x=(-2)^3*(-2)^4=(-2)^7

=>x=7

Answer 2

\(\dfrac{\left(-2\right)^x}{16}=-2^3\)
\(\Rightarrow\dfrac{\left(-2\right)^x}{2^4}=-2^3\)
\(\Rightarrow\left(-2\right)^x=-2^3\cdot2^4\)
\(\Rightarrow\left(-2\right)^x=-2^7\)
\(\Rightarrow x=7\)
#NoSimp

Answer 3

\(\dfrac{\left(-2\right)^x}{16}=-2^3\\ \Leftrightarrow\dfrac{\left(-2\right)^x}{16}=-8\\ \Leftrightarrow\left(-2\right)^x=-128\\ \Leftrightarrow\left(-2\right)^x=\left(-2\right)^7\\ \Leftrightarrow x=7\)

Answer 4

\(\dfrac{\left(-2\right)^x}{16}=-2^3\\ \Rightarrow\dfrac{\left(-2\right)^x}{16}=-8\\ \Rightarrow\left(-2\right)^x=-128\\ \Rightarrow\left(-2\right)^x=-2^7\\ \Rightarrow x=7\)