Question

(2x-1)^3-(x+3)^3=0

Answer 1

=>(2x-1-x-3)(4x²-4x+1+2x²+6x-x-3+x²+6x+9)=0

=>x-4=0

hay x=4

Answer 2

\((2x-1)^3-(x+3)^3=0\)

\(=(2x-1)-(x+3)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=1\\x=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-3\end{matrix}\right.\)