Question

(2x + 1)^2 = 9

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Answer 1

`(2x+1)^2=9`

`(2x+1)^2=3^2=(-3)^2`

TH1: `2x+1=3`

`2x=2`

`x=1`

TH2: `2x+1=-3`

`2x=-4`

`x=-2`

Answer 2

(2x + 1)² = 9

(2x + 1)² = 3²

\(\Rightarrow\)Trường hợp 1:                 

  2x + 1 = 3                             

  2x = 3 - 1

  2x = 2

  x = 2 : 2

  x = 1

Trường hợp 2:

  2x + 1 = -3

  2x = -3 - 1

  2x = -4

  x = -4 : 2

  x = -2

x \(\in\) \(\left\{-2;1\right\}\)

Answer 3

Ta có: \(\left(2x+1\right)^2=9\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+1=3\\2x+1=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=2\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)