Question

(2n^3 +3n^2 -5n+8 ) chia hết cho (n-2)

Answer 1

\(2n^3+3n^2-5n+8⋮n-2\)

=>\(2n^3-4n^2+7n^2-14n+9n-18+26⋮n-2\)

=>\(26⋮n-2\)

=>\(n-2\in\left\{1;-1;2;-2;13;-13;26;-26\right\}\)

=>\(n\in\left\{3;1;4;0;15;-11;28;-24\right\}\)