Question

2.[(7–33:33):22+99]–100

Answer 1

\(=2.\left[\left(7-1\right):22+99\right]-100\\ =2.\left(6:22+99\right)-100\\ =2.\left(\dfrac{3}{11}+99\right)-100\\ =2.\left(\dfrac{3}{11}+\dfrac{1089}{11}\right)-100\\ =2.\dfrac{1092}{11}-100\\ =\dfrac{2184}{11}-100\\ =\dfrac{1084}{11}\)

Answer 2

\(2.\left[\left(7-33:33\right):22+99\right]-100\)

\(=2.\left[\left(7-1\right):22+99\right]-100\)

\(=2.\left(6:22+99\right)-100\)

\(=2.\left(\dfrac{3}{11}+99\right)-100\)

\(=2.\dfrac{1092}{11}-100\)

\(=\dfrac{2184}{11}-100\)

\(=\dfrac{1084}{11}\)

Answer 3

=2*[(7-1):22+99]-100

=2*[3/11+99]-100

=2184/11-100

=1084/11