\(\left(25+2x\right)^3.5-3^2=4^2\\ \left(25+2x\right)^3.5=4^2+3^2=25\\ \left(25+2x\right)^3=\dfrac{25}{5}=5\)
Tới khúc này với toán 6 anh thấy số xấu quá em
\(\left(25+2x\right)^3.5-3^2=4^2\)
\(\Rightarrow\left(25+2x\right)^3.5=25\)
\(\Rightarrow\left(25+2x\right)^3=5\)
\(\Rightarrow2x+25=\sqrt[3]{5}\)
\(\Rightarrow x=\dfrac{\sqrt[3]{5}-25}{2}\)
Vậy ...
Sửa: \(\left(25+2x\right)^3:5-3^2=4^2\)
\(\Rightarrow\left(25+2x\right)^3:5-9=16\)
\(\Rightarrow\left(25+2x\right)^3:5=16+9\)
\(\Rightarrow\left(25+2x\right)^3:5=25\)
\(\Rightarrow\left(25+2x\right)^3=125\)
\(\Rightarrow25+2x=5\)
\(\Rightarrow2x=-20\)
\(\Rightarrow x=-10\)
(25+2x)3.5-32=42
(25+2x)3.5=42+32
(25+2x)3.5=16+9
(25+2x)3.5=25
(25+2x)3=25:5
(25+2x)3=5
sao sao ý