Question

2/5 * 2/9 + 2/5 : 9/7 + 2 và 2/5

8/9 : ( 1/11 - 5/12) + 5/9 : ( 1/15 - 2/3)

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Answer 1

Ta có: 

\(\dfrac{2}{5}\cdot\dfrac{2}{9}+\dfrac{2}{5}:\dfrac{9}{7}+2\)

\(=\dfrac{2}{5}\cdot\dfrac{2}{9}+\dfrac{2}{5}\cdot\dfrac{7}{9}+2\)

\(=\dfrac{2}{5}\cdot\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+2\)

\(=\dfrac{2}{5}\cdot1+2\)

\(=\dfrac{2}{5}+2\)

Ta thấy \(\dfrac{2}{5}+2>\dfrac{2}{5}\)

Vậy: \(\dfrac{2}{5}\cdot\dfrac{2}{9}+\dfrac{2}{5}:\dfrac{9}{7}+2>\dfrac{2}{5}\)

_________________________

\(\dfrac{8}{9}:\left(\dfrac{1}{11}-\dfrac{5}{12}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)

\(=\dfrac{8}{9}:-\dfrac{43}{132}+\dfrac{5}{9}:-\dfrac{3}{5}\)

\(=\dfrac{8}{9}\cdot-\dfrac{132}{43}+\dfrac{5}{9}\cdot-\dfrac{5}{3}\)

\(=-\dfrac{352}{129}+-\dfrac{25}{27}\)

\(=\dfrac{-4243}{1161}\)