Ta có: \(\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+...+\dfrac{2}{111\cdot113}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{111}-\dfrac{1}{113}\)
\(=\dfrac{1}{3}-\dfrac{1}{113}\)
\(=\dfrac{110}{339}\)
2/3x5 + 2/5x7 + ....+2/111x113
=1/3-1/5 + 1/5 - 1/7 +....+1/111-1/113
=1/3 - 1/113
=110/339