b^2=ac
=>b/a=c/b=k
=>b=ak; c=bk=ak*k=ak^2
\(\dfrac{a^2+b^2}{b^2+c^2}=\dfrac{a^2+a^2k^2}{a^2k^2+a^2k^4}=\dfrac{1}{k^2}\)
\(\dfrac{a}{c}=\dfrac{a}{ak^2}=\dfrac{1}{k^2}\)
=>\(\dfrac{a^2+b^2}{b^2+c^2}=\dfrac{a}{c}\)
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