Question

16x^2-(4x+1)^2=0

tìm x giải hộ mik

Answer 1

16x² - (4x+1)² = 0

16x² - (16x²+8x+1) = 0

16x² -16x² - 8x-1=0

-8x-1=0

-8x=1

x= 1/-8

Answer 2

\(\Leftrightarrow-8x-4=0\)

hay \(x=-\dfrac{1}{2}\)

Answer 3

⇔
−
8
x
−
4
=
0

hay  
x
=
−
1
2

⇔
−
8
x
−
4
=
0

hay  
x
=
−
1
2