Question

1/2x (4x-5) -2^2-18=0

Answer 1

x đầu tên là nhân hay x cần tìm vậy ạ

Answer 2

\(\dfrac{1}{2}x\left(4x-5\right)-2^2-18=0\)

\(\Leftrightarrow2x^2-\dfrac{5}{2}x-22=0\)

\(\Leftrightarrow\left(x-4\right)\left(2x+\dfrac{11}{2}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{11}{4}\end{matrix}\right.\)

Answer 3

\(\dfrac{1}{2}.\left(4x-5\right)-2^2-18=0\\ \Rightarrow\dfrac{1}{2}.\left(4x-5\right)-22=0\\ \Rightarrow\dfrac{1}{2}.\left(4x-5\right)=22\\ \Rightarrow4x-5=22:\dfrac{1}{2}\\ \Rightarrow4x-5=44\\ \Rightarrow4x=49\\ \Rightarrow x=\dfrac{49}{4}\)

    \(Vậy...\)

Answer 4

\(\dfrac{1}{2}x\left(4x-5\right)-2x^2-18=0\)

\(\Leftrightarrow x\cdot\dfrac{-5}{2}=18\)

hay \(x=-\dfrac{36}{5}\)