Question

\(125\%.\left(\dfrac{-1}{2}\right)^2:\left(1\dfrac{5}{16}-1,5\right)+2008^0\)

Answer 1

\(=\dfrac{5}{4}\cdot\dfrac{1}{4}:\left(\dfrac{21}{16}-\dfrac{24}{16}\right)+1=\dfrac{5}{16}\cdot\dfrac{16}{-3}+1=\dfrac{-5}{3}+1=-\dfrac{2}{3}\)