ĐKXĐ: x<>0
\(\dfrac{1}{2}=\dfrac{3x+1}{3x}\)
=>\(2\left(3x+1\right)=3x\)
=>6x+2=3x
=>3x=-2
=>\(x=-\dfrac{2}{3}\left(nhận\right)\)
Cho R(x) = 2x 2 + 3x - 1; M(x) = x 2 - x 3 thì R(x) - M(x)=
A.-3x 3 + x 2 + 3x – 1 B. -3x 3 - x 2 + 3x – 1
B. 3x 3 - x 2 + 3x – 1 D. x 3 + x 2 + 3x + 1
b1:
[4+2x]=-3x [3x-1]+2=x
[x+15]+1=3x [2x-5]+x=2
b2:
[2x-5]=x+1 [3x-2]-1=x
[3x-7]=2x+1 [2x-1]+1=x
Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
tìm x:|5(3x+1)|+|2(3x+1)|+|3x+1|=4
tìm x: 5(3x+1)|+|2(3x+1)|+|3x+1|=4
tìm x: 5(3x+1)|+|2(3x+1)|+|3x+1|=4
tìm x:|5(3x+1)|+|2(3x+1)|+|3x+1|=4
Thu gọn đa thức sau
Q=x^2 + 2xy - 3x^3 + 2y^3+3x^3-y^3
P=1/3x^y+ xy^2-xy+1/2xy^2-5xy-1/3x^2y
Tìm nghiệm : a) (2x-3).(2x+3) B)(x-4).(x-1).(x-2) C)2x(3x-1)-3x(5+2x) D)(3x-2).(3x+2)-4.(x-1)
làm tính chia:
a)( x^2 +3x -2):(x-1)
b) (3x^2-3x+1):(x+2)
