Question

[1/2 - (x+3)^2] : 5/4 = -2,8

Tìm x

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Answer 1

\(\left[\dfrac{1}{2}-\left(x+3\right)^2\right]:\dfrac{5}{4}=-2,8\)

=>\(\dfrac{1}{2}-\left(x+3\right)^2=-2,8\cdot\dfrac{5}{4}=-3,5\)

=>\(\left(x+3\right)^2=\dfrac{1}{2}+\dfrac{7}{2}=4\)

=>\(\left[{}\begin{matrix}x+3=2\\x+3=-2\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=-1\\x=-5\end{matrix}\right.\)