1+1/2+1/3+1/4+...+1/2^100-1 chứng minh rằng 50<A<100
Tính:
M=(1-1/2^2).(1-1/3^2).(1-1/4^2)...(1-1/49^2).(1-1/50^2)
N=(3/2-2/2^2).(4/3-2/3^2).(5/4-2/4^2)...(100/99-2/99^2).(101/100-2/100^2)
Cho A=1+1/2+1/3+1/4+...+1/2^100-1.Chứng tỏ rằng 50<A<100
câu 1
a) ( 100 - 1^2 ) * ( 100 - 2^2 ) * ( 100 - 3^2 ) * ...... * ( 100 -50^2 )
b) 1^0 + 1^2 + 1^3+ 1^4 +..........+1^99
Bài 4: Tính tổng 1) 1 + (-2) + 3 + (-4) + . . . + 19 + (-20) 2) 1 – 2 + 3 – 4 + . . . + 99 – 100 3) 2 – 4 + 6 – 8 + . . . + 48 – 50 4) – 1 + 3 – 5 + 7 - . . . . + 97 – 99 5) 1 + 2 – 3 – 4 + ... + 97 + 98 – 99 - 100
(3/1+2)+(3/1+2+3)+(3/1+2+3+4)+...+(3/1+2+3+..+50)-0.5X=1/100
3\1+2+3\1+2+3+3\1+2+3+4+3\1+2+3+...+50-0.5x=1\100
3/1+2+ 3/1+2+3+ 3/1+2+3+4+ 3/1+2+3+4+......+50-0.5*x=1/100
1/. 1 - 2 + 3 - 4 + ...+ 99 - 100
2/. 2 - 4 + 6 - 8 + ... + 48 - 50
3/. 1 + 2 - 3 - 4 + ... + 97 + 98 - 99 - 100
1+1/2+1/3+1/4+...+1/2^100-1 > 50