\(\dfrac{1}{12}+x=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}-\dfrac{1}{12}\)
\(x=\dfrac{2}{3}\)
\(\dfrac{1}{12}+x=\dfrac{3}{4}\\ x=\dfrac{3}{4}-\dfrac{1}{12}\\ x=\dfrac{9}{12}-\dfrac{1}{12}\\ x=\dfrac{8}{12}=\dfrac{2}{3}\)
\(\dfrac{x+1}{12}=\dfrac{3}{4}\Rightarrow x+1=9\Leftrightarrow x=8\)
\(\dfrac{1}{12}\)+x=\(\dfrac{3}{4}\)
x=\(\dfrac{3}{4}\)-\(\dfrac{1}{12}\)
x=\(\dfrac{2}{3}\)