`10x-15-x^2=0`
`<=>-x^2 +10x -15=0`
`Δ=b^2 -4ac=10^2 -4.(-1).(-15)=40`
`x_1 =` \(\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{-10+\sqrt{40}}{2.\left(-1\right)}=5-\sqrt{10}\)
`x_2 =` \(\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{-10-\sqrt{40}}{2.\left(-1\right)}=5+\sqrt{10}\)