1: =>(x+9)(x-5)=0
=>x=-9 hoặc x=5
2: =>(x+7)(x-5)=0
=>x=-7 hoặc x=5
3: =>(x+3)(x+5)=0
=>x=-3 hoặc x=-5
4: =>(x-8)(x+2)=0
=>x=8 hoặc x=-2
1: =>(x+9)(x-5)=0
=>x=-9 hoặc x=5
2: =>(x+7)(x-5)=0
=>x=-7 hoặc x=5
3: =>(x+3)(x+5)=0
=>x=-3 hoặc x=-5
4: =>(x-8)(x+2)=0
=>x=8 hoặc x=-2
1) (4-3x) (10x-5)=0
2) (7-2x) (4+8x) = 0
3) (9-7x) (11-3x) = 0
4) (7-14x) (x-2) = 0
5) (2x+1) (x-3) = 0
6) (8-3x) (-3x+5) = 0
7) (16-8x) (2-6x) = 0
8) (x+4) (6x-12) = 0
9) (11-33x) (x+11) = 0
10) (x-1/4) (x+5/6) = 0
11) (7/8-2x) (3x+1/3) = 0
12) 3x - 2x^2 = 0
13) 5x + 10x^2 = 0
14) 4x + 3x^2 = 0
15) -8x^2 + x =0
16) 10x^2 - 15x = 0
17) x^2 -4 =0
18) 9 - x^2 = 0
19) x^2 -1 = 0
20) (x-3) (2x-1) = (2x-1) ( 2x+3)
21) (5+4x) (-x+2) = (5+4x) (7+5x)
22) (4+x) (x-5) = (3x-8) (x-5) = 0
23) (3x-8) (7-21x) - (9+2x) (7-21x)
24) (10+ 7x) (x+1) = (9x-2)(x-1)
25) (9x-4) (x-1/2) - (x-1/2) (6+x) = 0
26) 9x^2 - 1 = (3x-1) (x+4)
27) (x+7) (3x+1) = 49-x^2
28) (2x+1)^2 = (x-1)^2
29)x^3- 5x^2+6x = 0
30) 3x^2 + 5x + 2 = 0
Giảii giúpp mìnhh đyy mọii ngườii .
Tìm x
a,(x2-4x+16)+(x+4)-x*(x+1)*(x+2)+3x2=0
b,(8x+2)*(1-3x)+(6x-1)*(4x-10)=-50
c,(x2+2x+4)*(2-x)+x*(x-3*(x+4))-x2+24=0
d,(x/2+3)*(5-6x)+(12x-2)*(x/4+3)=0
Tìm x biết
a)(x+3)^2(x-2)^2=2x b)7x(x-2)=(x-2) c)8x^3-12x^2+6x-1=0
d)4x^2-9-x(2x-3)=0 e)x^3+5x^2+9x=-45 f)x^3-6x^2-x+30=0
tìm x biết
(x+3)^2-(x-2)^2=2x
b> 7x(x-2)=(x-2)
c> 8x^3-12x^2+6x-1=0
d>4x^2-9-x(2x-3)=0
e>x^3+5x^2+9x=-45
f>x^3-6x^2-x+30=0
g> x^2+16=10x
tìm x: part 1 : a,(x^3)^2-(x+1)(x-1)=1 b,(x-2)^2-3(x-2)=0 c,(x+2)(x^2-2x+4)-x(x^2+2)=15 d,(x+1)^2-(x+1)(x-2)=0 e,4x(x-2017)-x+2017=0 f,(x+4)^2-16=0 part 2: a,x^3+27+(x+3)(x-9)=0 b,(2x-1)^2-4x^2+1=0 c,2(x-3)+x^2-3x=0 d,x^2-2x+1=6x-6 e,x^3-9x=0
(x^2+6x+8)(x^2+8x+15)-24=0
(x^2+x-2)(x^2+9x+18)-28=0
(x^2-1)^2-x(x^2-1)-2x^2=0
(x^2+4x+8)^2+3x(x^2+4x+8)+2x^2=0
Tìm x:
a,(x + 3)^2-(x-2)^2=2x
b,7x(x-2)=(x-2)
c,8x^3- 12x^2+6x-1=0
d,4x^2-5-x(2x-3)=0
e,x^3+5x^2+9x=-45
f,x^3-6x^2-x+30=0
g,x^2+16=10x
Mọi người giúp mình đi mà,mai mình phải nộp rồi,cảm ơn trước!!!!!!!!!!!!!!!!!!
1. Phân tích đa thức thành nhân tử: a) (x+4)^2+8x(x+4)^3+15x^2
2. Tìm x: a) 3x(x-2020)-x+2020=0
b)(2x-3).(3x+2)-6x^2=1
c)(3x-1)^2-(x+5)^2=0
d)4x^2-4x-35=0
a)(x^2 -1)^2-x(x^2-1)-2x^2=0
b)(x^2 + 6x+8)(x^2+8x+15)-24=0
c)(x^2+ x- 2)*(x^2+ 9x+18)-28=0
d)(x^2 +4x+8)^2+3x(x^2+4x+8)+2x^2=0