a: Thay x=2/3 vào A, ta được:
\(A=\dfrac{3\cdot\dfrac{2}{3}+2}{\dfrac{2}{3}}=\dfrac{2+2}{\dfrac{2}{3}}=4\cdot\dfrac{3}{2}=6\)
b: \(B=\dfrac{x^2-2}{x\left(x+2\right)}+\dfrac{1}{x+2}=\dfrac{x^2-2+x}{x\left(x+2\right)}\)
\(=\dfrac{x^2+x-2}{x\left(x+2\right)}=\dfrac{\left(x+2\right)\left(x-1\right)}{x\left(x+2\right)}=\dfrac{x-1}{x}\)