Question

0,1+\(\dfrac{16}{9}\)+11,1\(\dfrac{-20}{9}\)

giúp mình với

Answer 1

\(0,1+\dfrac{16}{9}+11,1-\dfrac{20}{9}\)

\(=0,1+11,1-\dfrac{4}{9}\)

\(=11,2-\dfrac{4}{9}=\dfrac{56}{5}-\dfrac{4}{9}=\dfrac{56\cdot9-4\cdot5}{45}=\dfrac{484}{45}\)