Xét ΔABC có \(\widehat{ABC}+\widehat{ACB}+\widehat{BAC}=180^0\)
=>\(\widehat{ABC}=180^0-30^0-75^0=75^0\)
=>\(\widehat{ABC}=\widehat{ACB}\left(=75^0\right)\)
=>ΔABC cân tại A
=>AB=AC=4
\(S_{ABC}=\dfrac{1}{2}\cdot AB\cdot AC\cdot sinBAC=\dfrac{1}{2}\cdot4\cdot4\cdot sin30=4\)