Câu hỏi của Diệu Hà Thịnh

\(\left(2x-1\right)^2-\left(5x-5\right)^2=0\)\(\Leftrightarrow\left(2x-1+5x-5\right)\left(2x-1-5x+5\right)=0\)\(\Leftrightarrow\left(7x-6\right)\left(-3x+4\right)=0\)\(\Rightarrow\left[{}\begin{matrix}7x-6=0\\-3x+4=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{6}{7}\\x=\dfrac{4}{3}\end{matrix}\right.\)Câu trả lời: \(\left(2x-1\right)^2-\left(5x-5\right)^2=0\)\(\Leftrightarrow\left(2x-1+5x-5\right)\left(2x-1-5x+5\right)=0\)\(\Leftrightarrow\left(7x-6\right)\left(-3x+4\right)=0\)\(\Rightarrow\left[{}\begin{matrix}7x-6=0\\-3x+4=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{6}{7}\\x=\dfrac{4}{3}\end{matrix}\right.\)