\(\dfrac{2}{3}\cdot\dfrac{4}{9}\cdot\dfrac{8}{27}=\dfrac{2}{3}\cdot\left(\dfrac{2}{3}\right)^2\cdot\left(\dfrac{2}{3}\right)^3=\left(\dfrac{2}{3}\right)^{1+2+3}=\left(\dfrac{2}{3}\right)^6\)
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