Ẩn danh
NT

i: \(4^3\cdot5+\left\{30\cdot\left[\dfrac{\left(12+2^3\right)}{5}+5^2\right]\right\}\)

\(=64\cdot5+\left\{30\cdot\left(\dfrac{20}{5}+25\right)\right\}=320+30\cdot\left(4+25\right)\)

\(=320+30\cdot29\)

=320+870

=1190

k: \(38+10^2:\left[345-\left(3^2\cdot5+2^3\cdot5^2\right)\right]\)

\(=38+100:\left[345-\left(9\cdot5+8\cdot25\right)\right]\)

\(=38+100:\left(345-45-200\right)=38+100:100=38+1=39\)

l: \(40-40:\left\{520:\left[500-\left(130+30\cdot8\right)\right]\right\}\)

\(=40-40:\left\{520:\left[500-130-240\right]\right\}\)

\(=40-40:\left\{520:130\right\}=40-40:4=40-10=30\)

n: \(100:\left\{250:\left[450-\left(4\cdot5^3-2^2\cdot25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-4\cdot125+4\cdot25\right]\right\}\)

\(=100:\left\{250:\left(450-500+100\right)\right\}\)

\(=100:\left\{250:50\right\}=\dfrac{100}{5}=20\)

o: \(\left[504-\left(25\cdot8+70\right)\right]:9-15+19^0\)

\(=\left(504-200-70\right):9-15+1\)

\(=\dfrac{234}{9}-14=26-14=12\)

ô: \(\left[1104-\left(25\cdot8+40\right)\right]:9+3^{16}:3^{12}\)

\(=\left(1104-200-4\right):9+3^4\)

\(=900:9+81=100+81=181\)

ơ: \(2^5\cdot3+4\left[\left(26-22\right)^2:4+6\right]-76^0\)

\(=32\cdot3+4\cdot\left(4^2:4+6\right)-1\)

\(=95+4\cdot\left(4+6\right)=95+40=135\)

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H24
31 tháng 8 lúc 9:28

`i, 4^3 . 5 + {30.[(12 + 2^3) : 5 + 5^2]}`

` = 64 . 5 + {30.[(12 + 8) : 5 + 25 ]}`

`= 64 . 5 + {30.[20 : 5 + 25]}`

`= 64 . 5 + {30. [4 + 25]}`

`= 64 . 5 + {30 . 29}`

`= 320 + 870`

`= 1190`

 

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H24
31 tháng 8 lúc 15:26

`k, 38 + 10^2 : [345 - (3^2 . 5 + 2^3 . 5^2)]`

` = 38 + 100 : [345 - (9 . 5 + 8 . 25)]`

` = 38 + 100 : [345 - ( 45 + 200)]`

` = 38 + 100 : [345 - 245]`

` = 38 + 100 : 100`

` = 38 + 1`

` = 39

`l, 40 - 40 : { 520 : [500 - (130 + 30 . 8)]}`

` = 40 - 40 :{520 : [500 - (130 + 240)]}`

` = 40 - 40 : {520 : [500 -  370]}`

` = 40 - 40 : {520 : 130}`

` = 40 - 40 : 4`

` = 40 - 10`

` = 30` 

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