Question

Answer 1

\(x^2< =4\)

=>-2<=x<=2

=>A=[-2;2]

B={x\(\in R\)|x<1

=>B=(-\(\infty\);1)

\(A\cup B=(-\infty;2]\)

\(A\cap B=[-2;1)\)

\(C_RB\)=R\B=[1;+\(\infty\))