\(\left(x-\dfrac{3}{2}\right)^2=\dfrac{9}{16}\\ =>\left(x-\dfrac{3}{2}\right)^2=\left(\dfrac{3}{4}\right)^2\\ TH1:x-\dfrac{3}{2}=\dfrac{3}{4}\\ =>x=\dfrac{3}{4}+\dfrac{3}{2}\\ =>x=\dfrac{9}{4}\\ TH2:x-\dfrac{3}{2}=-\dfrac{3}{4}\\ =>x=\dfrac{3}{2}-\dfrac{3}{4}\\ =>x=\dfrac{3}{4}\)
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