\(\dfrac{2}{3}x-\dfrac{1}{5}=\dfrac{1}{2}x+0,75\\ =>\dfrac{2}{3}x-\dfrac{1}{5}=\dfrac{1}{2}x+\dfrac{3}{4}\\ =>\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{3}{4}+\dfrac{1}{5}\\ =>\dfrac{1}{6}x=\dfrac{19}{20}\\ =>x=\dfrac{19}{20}:\dfrac{1}{6}\\ =>x=\dfrac{57}{10}\)
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