Câu hỏi của Cuuemmontoan

Gọi O là tâm đáy \(\Rightarrow AO=\dfrac{1}{2}AC=\dfrac{1}{2}.AB\sqrt{2}=\dfrac{a\sqrt{2}}{2}\)Pitago: \(SO=\sqrt{SA^2-AO^2}=\sqrt{\left(2a\right)^2-\left(\dfrac{a\sqrt{2}}{2}\right)^2}=\dfrac{a\sqrt{14}}{2}\)\(V=\dfrac{1}{3}SO.AB^2=\dfrac{a^3\sqrt{14}}{6}\)Câu trả lời: Gọi O là tâm đáy \(\Rightarrow AO=\dfrac{1}{2}AC=\dfrac{1}{2}.AB\sqrt{2}=\dfrac{a\sqrt{2}}{2}\)Pitago: \(SO=\sqrt{SA^2-AO^2}=\sqrt{\left(2a\right)^2-\left(\dfrac{a\sqrt{2}}{2}\right)^2}=\dfrac{a\sqrt{14}}{2}\)\(V=\dfrac{1}{3}SO.AB^2=\dfrac{a^3\sqrt{14}}{6}\)